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Investment Strategies / Mechanical Investing
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Author: agehlot   😊 😞
Number: of 3958 
Subject: DH10 RRS 126-2s slope
Date: 03/12/2024 11:08 AM
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I have a quick question for Elan and Jim.

As per the old Motley Fool posts from 1999, DH10 RRS 126-2s screen definition said: The regression line slope over the last 126 trading days, using log-price versus trading day.

And in one of the posts from Jim a year ago he mentioned the methodology as:
Take the prices for the last 6 months for the first stock, let's say in column A.
Take the log of all those prices = LN (a1) in column B.
Calculate the slope, =SLOPE (B1:B126,A1:A126).
As per Jim’s explanation above, the regression line slope is using log-price versus the “actual price” instead of trading days.

Which is the correct way to calculate the regression slope for DH10 RRS 126-2s?
Thanks in advance.
AJ
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Author: JohnIII   😊 😞
Number: of 3958 
Subject: Re: DH10 RRS 126-2s slope
Date: 03/12/2024 9:12 PM
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Which is the correct way to calculate the regression slope

I would have to think it's log-price vs trading day. I suspect Jim left out a column as he was thinking through the calculation. I suspect 'A' would be dates, 'B' = price, 'C' = LN(B). Then m = SLOPE(A, C).

But I'd certainly like to know if I'm wrong about that.

John
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Author: elann 🐝 GOLD
SHREWD
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Number: of 3958 
Subject: Re: DH10 RRS 126-2s slope
Date: 03/15/2024 7:46 PM
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I would have to think it's log-price vs trading day. I suspect Jim left out a column as he was thinking through the calculation. I suspect 'A' would be dates, 'B' = price, 'C' = LN(B). Then m = SLOPE(A, C).

But I'd certainly like to know if I'm wrong about that.


I believe you're absolutely right.

Elan
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